3.1 In this section we prove the following statement
Let be a closed three-manifold, and let
be a
smooth solution to the Ricci flow on a finite time interval
Suppose that
is a compact
family. Then for any
one can construct a continuous
deformation
such that for
each curve
either the value
is
bounded from above by
plus the value at
of the
solution to the ODE
with
the initial data
or
moreover, if
was a constant map, then all
are constant maps.
It is clear that our statement implies lemma 1.2, because a family consisting of very short loops can not represent a nontrivial relative homotopy class.
3.2 As a first step of the proof of the statement we
can replace by a family, which consists of piecewise
geodesic loops with some large fixed number of vertices and with
each segment reparametrized in some standard way to make the
parametrizations of the whole curves twice continuously
differentiable.
Now consider the manifold
and for each
consider the smooth embedded
closed curve
such that
and
where
and
are projections of
to the first and second factor
respectively, and
is the parameter of the curve
on the
standard circle of length one. Using 2.3 we can construct a
solution
to the curve shortening flow
with initial data
The required deformation will be
obtained as
(where
denotes the
family consisting of
) for certain sufficiently small
We'll verify that an appropriate
can be found for
each individual curve
or for any finite number of them, and
then show that if our
works for all elements of a
-net
in
for sufficiently small
then it works for all
elements of
3.3 In the following estimates we shall denote by
large constants that may depend on metrics
family
and
but are independent of
and a particular curve
The first step in 3.2 implies that the lengths and total
curvatures of
are uniformly bounded, so by 2.1 the same
is true for all
It follows that the area swept by
is bounded above by
and therefore we have the estimates
3.4 It follows from (5) that
for any
Fix some large constant
to
be chosen later. Then there is a subset
of measure at least
where
hence
on any arc of length
Assuming that
are at least that long, we can
apply 2.2 and construct another subset
of measure at least
consisting of
finitely many intervals of measure at least
each,
such that for any
we have pointwise estimates
on
for curvature and higher derivatives, of the form
Now fix and consider any sequence of
Assume again that the lengths of
are bounded below by
at least for
where
Then an elementary argument shows that we can
find a subsequence
and a subset
of measure at least
consisting of
finitely many intervals, such that
for all
It follows that on every interval of
the curve shortening flows
smoothly converge
(as
in some subsequence of
) to a curve
shortening flow in
Let be the solution of the ODE
with initial data
Then for sufficiently
small
we have
provided that
Indeed, on the
intervals of
we can estimate the change of
for the
limit flow using the minimal disk argument as in 1.2, and this
implies the corresponding estimate for
if
is small enough, whereas for the intervals of
the complement of
we can use the estimate in 3.3.
On the other hand, if our assumption on the lower bound for
lengths does not hold, then it follows from (5) that
3.5 Now apply the previous argument to all elements
of some finite -net
for small
to
be determined later. We get a
such that for each
either
or
Now for any curve
pick a curve
-close to
and apply the result of
2.4. It follows that if
and
then
On the other hand,
if
then we can
conclude that
provided that
is
small enough in comparison with
and
Indeed, if
then
for all
on the other hand, using (5) we can find a
such that
for
hence,
applying 2.5, we get
for this
which is incompatible with
The proof of the statement 3.1 is complete.